# Squishy Thinking

## Optimizing (part of) a Kakuro puzzle solver in Julia

02 Nov 2015

Kakuro is a number puzzle that is a bit like a combination between Sudoku and a crossword puzzle. Imagine a crossword puzzle where, instead of words, blocks of boxes are filled with combinations of digits between 1 and 9, and instead of clues about words, you are given sums that a block of digits must add up to.

When you’re solving a Kakuro puzzle, it’s helpful to be able to generate all the combinations of m different digits that add up to a given sum. A recent thread on the julia-users mailing list considered how to implement this task efficiently on a computer.

In this post, I’d like to show a progression of a few different implementations of the solution of this same problem. I think the progression shows off one of Julia’s core strengths: in a single language, you are free to think in either a high level way that is close to your problem domain and easy to prototype, or a low level way that pays more attention to the details of efficient machine execution. I don’t know any other system that even comes close to making it as easy to switch back and forth between these modes as Julia does.

Attention Conservation Notice: If you’re looking for information on how to solve Kakuro with a computer, you should probably look elsewhere. This post is a deep dive into a tiny, tiny subproblem. On the other hand, I’ll show how to speed up the solution of this tiny, tiny subproblem by a factor of either ten thousand or a million, depending how you count, so if that sounds fun you’re in the right place.

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## Bisecting Floating Point Numbers

22 Feb 2014

Bisection is about the simplest algorithm there is for isolating a root of a continuous function:

1. Start with an interval such that the function takes on oppositely signed values on the endpoints.
2. Split the interval at its midpoint.
3. Recurse into whichever half has endpoints on which the function takes on oppositely signed values.

After each step, the new interval is half as large as the previous interval and still contains at least one zero (by the Intermediate Value Theorem).

I want to highlight a couple of interesting issues that arise when implementing bisection in floating point arithmetic that you might miss if you just looked at the definition of the algorithm.

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